The x and y coordinates of the track are related in dimensionless units by y=\frac{x^2}{4}, where the positive y-axis is in the vertical downward direction. As the particle slides down the track, what is its tangential acceleration?
- 0
- g
- \frac{gx}{2}
- \frac{gx}{\sqrt{x^2+4}}
- \frac{gx^2}{\sqrt{x^2+16}}
Solution :
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