Assume no friction between the cube and the wedges, but a coefficient of static friction $\mu < 1$ between the wedges and the floor. What is the largest $M$ that can be balanced as shown without motion of the wedges?

- $\frac{m}{\sqrt{2}}$
- $\mu\frac{m}{\sqrt{2}}$
- $\mu\frac{m}{1-\mu}$
- $2\mu\frac{m}{1-\mu}$
- All $M$ will balance.

Solution :

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