Assume no friction between the cube and the wedges, but a coefficient of static friction \mu < 1 between the wedges and the floor. What is the largest M that can be balanced as shown without motion of the wedges?
- \frac{m}{\sqrt{2}}
- \mu\frac{m}{\sqrt{2}}
- \mu\frac{m}{1-\mu}
- 2\mu\frac{m}{1-\mu}
- All M will balance.
Solution :
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