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Tuesday, 2 August 2011

Physics GRE - #1

It is possible that the Newtonian theory of gravitation may need to be modified at short range. Suppose that the potential energy between two masses m and m' is given by V(r)=-\frac{Gmm'}{r}(1-ae^{-\frac{r}{\lambda}})
For short distances r\ll \lambda calculate the force between m and m'.

  • F=-\frac{Gmm'}{r^2}
  • F=-\frac{Gmm'}{r^2}(1-a)
  • F=-\frac{Gmm'}{r^2}(1+a)
  • F=-\frac{Gmm'}{\lambda r}
To get the force, we take the negative derivative of the potential function, -V^\prime(r). \begin{eqnarray*} -V^\prime(r) & = & -\frac{Gmm'}{r^2}(1-ae^{-r/\lambda})-\frac{Gmm'}{r}(ae^{-r/\lambda}) \\                      & = & -\frac{Gmm'}{r^2}\left(1-ae^{-r/\lambda}\left(1+\frac{r}{\lambda}\right)\right) \end{eqnarray*}
When r\ll \lambda, we have F(r)\approx -\frac{Gmm'}{r^2}(1-a).

2 comments:

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[hide] Kevin said...

This also works if one takes a Taylor expansion of the potential first, then diferentiates to get the force.

on 4 August 2011 at 15:10
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[hide] Kazkek said...

So as far as I know the GRE is about the fastest possible way to get the answer. The fastest way to get the answer in this case is just to take

r/lambda = 0 then we get 1-a(e^0) = 1-a

we can do this because r is MUCHMUCH smaller than lambda

on 6 August 2011 at 09:14
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