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Sunday, 28 August 2011

Math GRE - #27

Which of the following is the best approximation of \sqrt{1.5}(266)^{3/2}?

  1. 1000
  2. 2700
  3. 3200
  4. 4100
  5. 5300

Solution :

Choice 5 is the answer.

With some simplification, we note that: \begin{eqnarray*} \sqrt{1.5}(266)^{3/2}=\sqrt{\frac{3}{2}}\cdot(266)^{3/2} & = & 266\sqrt{\frac{3\cdot 266}{2}} \\ & = & 266\sqrt{399}\approx266\cdot20\approx 5300. \end{eqnarray*}
Those of us familiar with Taylor series may try approximations with calculus, however this question teaches us that too much knowledge may be a little bit dangerous if misapplied. And that most of the time, there are simpler solutions than you'd think.

2 comments:

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[hide] Anonymous said...

Another technique is to roughly approximate the square of the given formula, which will be slightly greater than

[; 1.5 * 250^3 \sim 1.5 * 16000000 = 24000000.;]

The square root of that is nearly 5000, so the answer will be 5300.

on 29 August 2011 at 20:00
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[hide] Paul Liu said...

Hmm but you rounded up when you approximated 1.5*16000000 and then you rounded up again when you approximated 24000000 as 25000000 so I'm not entirely convinced.

on 29 August 2011 at 20:31
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