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Thursday, 1 September 2011
Physics GRE - #31
Which of the following is nearly the mass of the Earth? The radius of the Earth is about $6.4\cdot10^6\,\text{m}$.
$6\cdot10^{24}\,\text{kg}$
$6\cdot10^{27}\,\text{kg}$
$6\cdot10^{30}\,\text{kg}$
$6\cdot10^{33}\,\text{kg}$
$6\cdot10^{36}\,\text{kg}$
Solution :
Choice 1 is the answer.
If you don't remember the mass of the earth off the bat, recall that at ground level, \[mg=\frac{GmM_E}{R_E^2}\implies M=\frac{gR_E^2}{G}\] where $g$, $G$, and $R_E$ are given constants (a table of constants is given during the exam). We can plug in the numbers and compute \[M_E\approx6\cdot10^{24}\,\text{kg}.\]
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This webpage is LaTeX enabled. To type in-line formulae, type your stuff between two '$'. To type centred formulae, type '\[' at the beginning of your formula and '\]' at the end.
I was able to eliminate choices 3 through 5 because I knew the Sun was $>10^30$ kg (not much greater). What I should of remembered, which I feel is good to remember as a reality check" that ~1 million Earths could fit in the Sun. This fact would eliminate choice 2 and leave 1.
Knowing little things like that I feel help arrive at an answer faster than doing the calculation.
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This webpage is LaTeX enabled. To type in-line formulae, type your stuff between two '$'. To type centred formulae, type '\[' at the beginning of your formula and '\]' at the end.
Knowing little things like that I feel help arrive at an answer faster than doing the calculation.
Post a Comment